if (s1.compareTo(s2) != 0) { System.err.println("different!"); }
(updated later)
Nope, maybe not. Similar code is failing in my app. But then, this works as expected:
jcomeau@notebook /tmp
$ cat teststrings.java
public class teststrings {
public static void main(String[] argv) {
System.err.println("comparing " + argv[0] + " to "
+ argv[1] + ": " + argv[0].compareTo(argv[1]));
System.err.println("now with String.equals(): " + argv[0].equals(argv[1]));
}
}
jcomeau@notebook /tmp
$ java teststrings this that
comparing this to that: 8
now with String.equals(): false
jcomeau@notebook /tmp
$ java teststrings this this
comparing this to this: 0
now with String.equals(): true
last updated 2013-01-10 20:15:28. served from tektonic.jcomeau.com